Coin and change word problem

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franklin91

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Sep 14, 2010
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Johnny has $6.75 in dimes and quarters. He has 8 more dimes than quarters. HOw many quarters does Johnny have? HOw many dimes does he have?

i know how to do a set up of an original type of problem but the 8 more dimes is throwing me off....I cant seem to figure out how to set it up....I would appreciate the help thanks
 
franklin91 said:
Johnny has $6.75 in dimes and quarters. He has 8 more dimes than quarters. HOw many quarters does Johnny have? HOw many dimes does he have?

i know how to do a set up of an original type of problem but the 8 more dimes is throwing me off....I cant seem to figure out how to set it up....I would appreciate the help thanks
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Hi Johnny,

Let's solve this using only one equation.

Let q = the number of quarters Johnny has.

Let q + 8 = the number of dimes Johnny has (he has 8 more dimes than quarters.

Let 25q = the value in cents for all the quarters Johnny has.

Let 10(q + 8) = the value in cents for all the dimes Johnny has.

Let 675 = the total value in cents of all the dimes and quarters put together.

Can you build the equation with the above information? I bet you can!

 
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