Hello,I don't remember exactly how to finish
The product of three consecutive odd integers reduced by 23 is 99 less than the cube of the sum of the smallest number and 2. Compute the mean of the three integers.
(x)(x+2)(x+4)-23=(x+2)3-99
(x)(x+4)-23=(x+2)2-99
2x+4x=(x+2)2-76
6x=x2+4-76
x=x2/6-72/6
x=x2/6-12
x=x2-2
I don't think that i got it quite right?
The product of three consecutive odd integers reduced by 23 is 99 less than the cube of the sum of the smallest number and 2. Compute the mean of the three integers.
(x)(x+2)(x+4)-23=(x+2)3-99
(x)(x+4)-23=(x+2)2-99
2x+4x=(x+2)2-76
6x=x2+4-76
x=x2/6-72/6
x=x2/6-12
x=x2-2
I don't think that i got it quite right?