hello!
I have tried solving this problem, I realize it is extremely similar to the 'birthday problem,' but I still cannot figure out which formulas to use.
QUESTION: "In a class of 36 students, what is the probability that at least 2 people have the same birthday? Assume that there are 365 days in a calendar year. (You can do a search for the birthday problem and discover that in a group of 23 people, the probability is 0.507 that at least two have the same birthday.)"
So far, I have this:
36 students ---- 2 same birthday --- 365 days.
P(n) = 1 - P(n)
Probability that it's not: 36/2 = 36 * 35/2 = 630 pairs.
NOW, I'm lost after this.
I'd really appreciate the help, thank you in advance!!!
I have tried solving this problem, I realize it is extremely similar to the 'birthday problem,' but I still cannot figure out which formulas to use.
QUESTION: "In a class of 36 students, what is the probability that at least 2 people have the same birthday? Assume that there are 365 days in a calendar year. (You can do a search for the birthday problem and discover that in a group of 23 people, the probability is 0.507 that at least two have the same birthday.)"
So far, I have this:
36 students ---- 2 same birthday --- 365 days.
P(n) = 1 - P(n)
Probability that it's not: 36/2 = 36 * 35/2 = 630 pairs.
NOW, I'm lost after this.
I'd really appreciate the help, thank you in advance!!!