Statistics......I am really lost ....hellllppp

kahkah

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Jan 18, 2012
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A random sample of size 81 is drawn from a population with a standard deviationof 12. If only 18% of the time a sample mean greater than 300 is obtained, whatis the mean of the population?
 
Look up the z score for the top 18% in a z table. In other words, look up .82 in a z table and find its corresponding z score.

Set the formula \(\displaystyle \frac{(x-\mu)\sqrt{n}}{\sigma}\) equal to this z score, enter in your

knowns, and solve for \(\displaystyle \mu\)

You have \(\displaystyle x, \;\ \sigma, \;\ n\)
 
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