rahulranjan86
New member
- Joined
- Feb 18, 2012
- Messages
- 9
If 3 of 20 tyres are defective and 4 of them are randonly chosen for inspection, what is the probablity that only one of the defective tyres are included?
My Attempt:
= (3C1 * 17C3) / 20C4
= 0.4211
Book Answer: 0.889
Not sure where I am going wrong. :?:
My Attempt:
= (3C1 * 17C3) / 20C4
= 0.4211
Book Answer: 0.889
Not sure where I am going wrong. :?: