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SadAtMath
06-03-2012, 10:44 PM
Here it is:Suppose 5 students are randomly selected in a class of 42. How many selections are possible if 5 students are selected with the first winning $100, second $75, third $50, fourth $25, fifth $10. A student can win more than one.I don't even know where to start. Permutations? Combination? I feel like this has multiple steps, but of what I do not know. Thanks!

soroban
06-03-2012, 11:01 PM
Hello, SadAtMath!

Evidently, you are over-thinking the problem.


Suppose 5 students are randomly selected in a class of 42.
How many selections are possible if 5 students are selected with
the first winning $100, second $75, third $50, fourth $25, fifth $10.
A student can win more than one prize.

I don't even know where to start. Permutations? Combination?
I feel like this has multiple steps, but of what I do not know. Thanks!
There are 42 choices for the winner of the 1st prize.
There are 42 choices for the winner of the 2nd prize.
There are 42 choices for the winner of the 3rd prize.
There are 42 choices for the winner of the 4th prize.
There are 42 choices for the winner of the 5th prize.

Get it?

There are: .42^5 \:=\:130,\!691,\!232 possible selections.

SadAtMath
06-03-2012, 11:38 PM
Are you trying to tell me that there are 130691232 possible selections? That is, 42^5? I felt like with the various prizes available it would ve more difficult. Sheesh, probability really stumps me. Thanks!