Probability question!!

Hello, I am unsure of how to attempt this question because I do not understand it..

A three-digit number is to be formed from the digits 4,5,9 written on three seperate cards. What is the probability that:
a) the number formed is odd?
b) the number formed is even?
c) the number is less than 900?
d) the number is divisible by 5?

Help would be appreciated! Thankyou.

a)To be odd, the number has to end with the 9 or 5. So the numbers ending with 9 and 5 are: 459, 495, 549, and 945. The other numbers are: 594, and 954. So 4 out of the 6 numbers are odd. Thus the probability is 0.66666 recurring.
b)To be even, the number has to end with the 4. So the combinations ending with 4 are: 954, and 594. The other combinations are: 945, 549, 459, and 495. So 2 out of the 6 numbers are even. Thus the probability is 0.33333 recurring.
c)To be less than 900, obviously it can't start with the 9. So the combinations that don't start with 9 are: 495, 459, 549, 594. The other combinations are: 945, and 954. So 4 out of the 6 combinations are less than 900. Thus the probability is 0.66666 recurring.
d)To be divisible by 5, the 5 has to be at the end. So there are only 2 combinations that will allow for that: 495, and 945. Then there are the other combinations that don't have 5 at the end: 459, 954, 549, 594. So 2 out of the 6 are divisible by 5, thus the probability is 0.33333 recurring.

Hello, mathsistough!

Hello, I am unsure of how to attempt this question because I do not understand it.
What part don't you understand?

A three-digit number is to be formed from the digits 4, 5, 9 written on three separate cards.
Do you understand that?

What is the probability that:

a) the number formed is odd?
Do you know what an odd number is?

b) the number formed is even?
Do you know what an even number is?

c) the number is less than 900?
Do you know when a number is less than 900?

d) the number is divisible by 5?
Do you know when a number is divisible by 5?

Click to expand...

You have three cards: .\(\displaystyle \boxed{\begin{array}{c}\quad \\ 4\end{array}}\quad \boxed{\begin{array}{c}\quad\\5\end{array}} \quad \boxed{\begin{array}{c}\quad\\9\end{array}}\)


You arrange them in all possible orders.
There are 6 of them:.\(\displaystyle \begin{array}{cccccc} 459 & 495 & 549 & 594 & 945 & 954 \end{array}\)

Can you answer the questions now?