dumbledore
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- Sep 24, 2012
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solved
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What tkhunny meant was that all you need to do your computations are:Thanks for the reply
So a) E(x)= 840,000,000 (0.3) + 210,000,000 (0.7) = 399,000,000
I think your formula for variance is wrong, isnt is sum (x-E(x))^2 P(x)?
And when I use that I get b) variance= (840,000,000-399,000,000)^2 (0.3) + (210,000,000-399,000,000)^2 (0.7) which comes out to be a ridiculously large number
Thanks for the reply
So a) E(x)= 840,000,000 (0.3) + 210,000,000 (0.7) = 399,000,000
I think your formula for variance is wrong, isnt is sum (x-E(x))^2 P(x)?
And when I use that I get b) variance= (840,000,000-399,000,000)^2 (0.3) + (210,000,000-399,000,000)^2 (0.7) which comes out to be a ridiculously large number