Probability

billyb said:
A new disease breaks out: the Angry Chicken Disease (ACD). Scientists study the condition by looking at whether or not a person has an elevated white cell count and whether or not they have the disease. It is found that 22% of the people tested have an elevated white cell count. 17% have an elevated white cell count and ACD. Given that a person has ACD, there is an 85% chance that they have an elevated white cell count.
What is the probability that someone has ACD?
Or is my table inaccurate?
Click to expand...
From the given, your table is inaccurate.
You are given that \(\displaystyle P(e|a)=0.85~\&~P(a\cap e)=0.17~.\)

Now \(\displaystyle P(e|a)=\frac{P(a\cap e)}{P(a)}\).
So \(\displaystyle P(a)=~?\).
 
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