Can anyone help me figure out how to get started on this problem from my assignment? I'm not asking for the answers, rather I'd like to know what steps should be taken to solve the problem. Any help would be appreciated, thanks.
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I'll give you a hint for (a). You want P(~Y). It may help to ask yourself, what is the probability that I will choose ~Y from the two Z groups. So you must find the marginal distribution for ~Y for both Z and ~Z as it occurs in both groups. For Z, P(~Y) = 0.36 (do you see how I got that?), yet P(Z) = 0.60 (again, do you see how I got that?). Thus, P(~Y) for the Z group is (0.36)*(0.60) = 0.216.
Now try and find P(~Y) for the ~Z group. Then what do you think you do with these two amounts?