Quest. 17

CAC

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Help! Question. Before 1918 55% of wolves were male, 45% of wolves were female, from 1918 to present, 70% of wolves were male, 30% of wolves were female, before 1918 in a random sample of 12 wolves in the area, what was the probability that 6 were male? What was the probability that 6 were female?
 
Help! Question. Before 1918 55% of wolves were male, 45% of wolves were female, from 1918 to present, 70% of wolves were male, 30% of wolves were female, before 1918 in a random sample of 12 wolves in the area, what was the probability that 6 were male? What was the probability that 6 were female?

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Help! Question. Before 1918 55% of wolves were male, 45% of wolves were female, from 1918 to present, 70% of wolves were male, 30% of wolves were female, before 1918 in a random sample of 12 wolves in the area, what was the probability that 6 were male? What was the probability that 6 were female?

First, do NOT "hi-jack" someone else's thread to ask a separate question. In addition to being rude, that reduces your chances of getting a response. Instead, start a new thread with the "new thread" button.

In any case, "before 1918" the probability that any one wolf being male was .55, the probability of any one wolf being female was .45. The probability of 6 out of a sample of 12 wolves being male is \(\displaystyle \begin{pmatrix}12 \\ 6\end{pmatrix}(.55)^6(.55)^6(.45)^6= \frac{12!}{6!6!}(.55)^6(.45)^6\). And if 6 out of 12 wolves are male, then the other 6 must be female so the probability that 6 out of 12 are female is exactly the same.
 
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