data and probability help needed 4th grade

heyjoshidude said:

I have a problem that says : Adrian (A) , Dakota (D) and Calvin (C) made an average of 52 snacks. Adrian and Dakota Adrian and Dakota made an average of 61 snacks. Dakota and Calvin made an average of 44 snacks. How many snacks did each of them make?
Total = Mean x # of children = _52___ x __3__= __156__
A & D's average __61 x __2__= __122__
D & C's average __44__x__2__= __88__HERE IS WHERE I AM STUCK:
C _____ - ______ = _______ snacks
D _____ - ______ = _______ snacks
A _____ - ______ = _______ snacks
No additional information provided. Please help thanks! Heydudejoshi :grin:

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Subhotosh Khan said:

A + D + C = 156 .................................................(1)

A + D = 122 ........................................................(2)

C + D = 88 ..........................................................(3)

So subtract (2) from (1) [(1) - (2)]

(A + D + C) - (A + D) = 156 - 122

C = 34................................................................(4)

subtract (4) from (3) [(3) - (4)]

(C + D) - (C) = 88 - 34

What do you get?

continue....

This is pretty tough problem for 4th. grader!!!

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