Data collected by child development scientists produced thisconfidence interval for the average age (in weeks) at which babies begin tocrawl.
t-Interval for µ (95.00% Confidence) : 29.202 < µ (age) < 31.844
Explain carefully what the software output means.
What is the margin of error for this interval?
If the researcher had calculated a 90% confidence interval, would the marginof error be larger or smaller? EVDB-23-10: Crawling Data collected byscientists produced a CI for the average crawling age in weeks.
t-Interval for µ @95% Confidence Interval: 29.202 < µ (age) < 31.844
This output means:
We are 95% confident that the average age parameter is in between 29.2 and31.8 weeks.
ME for this interval: (31.844-29.202)/2 = ±1.321
If using a 90% CI, the margin of error be larger or smaller? Explain.
If a 90% CI is used, then, the z* value gets smaller, in turn, the margin oferror also decreases.
Is the above problem answered correctly?
t-Interval for µ (95.00% Confidence) : 29.202 < µ (age) < 31.844
Explain carefully what the software output means.
What is the margin of error for this interval?
If the researcher had calculated a 90% confidence interval, would the marginof error be larger or smaller? EVDB-23-10: Crawling Data collected byscientists produced a CI for the average crawling age in weeks.
t-Interval for µ @95% Confidence Interval: 29.202 < µ (age) < 31.844
This output means:
We are 95% confident that the average age parameter is in between 29.2 and31.8 weeks.
ME for this interval: (31.844-29.202)/2 = ±1.321
If using a 90% CI, the margin of error be larger or smaller? Explain.
If a 90% CI is used, then, the z* value gets smaller, in turn, the margin oferror also decreases.
Is the above problem answered correctly?