Elementary Statistics

paulacutino

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[FONT=&quot]Games – fifty – six of electronic gamers play games online, and sixty – four percent of those gamers are female. What is the probability that a randomly selected gamer plays games online and is male?[/FONT]
 
Well 64% of 56% is what %?

Thats the percent of female online gamers out of all gamers. So subtract that from 56% to get the percentage of male online gamers. Then put that over 100 and reduce to get the probability.
 
number of players is irrelevant; we have 64% female, so 36% male.
Denis. I suspect that the original post is badly worded and that mackdaddy may have deciphered it correctly. If the actual question says that 56 PERCENT of electronic gamers play online and that 64% of the gamers who play online are female, then the probability of picking an electronic gamer who is male and an online gamer is indeed p(M + O) = p(M|O) * p(O) = 0.56 * (1.00 - 0.64) = 0.56 * 0.36 = 0.2016 = 20.16%. Obviously, if the original post is correct, then your post is correct, but the original post does not make much sense. Mackdaddy could have improved the clarity of his answer by explaining what question he was answering, but this was effectively his first post as a tutor.
 
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