Need help please

conniejoy

New member
Joined
Apr 5, 2013
Messages
2
In the formula for the variance of values in a sample, Σ (x – xbar)^2/n-1, what is required for the variance to equal zero?
 
In the formula for the variance of values in a sample, Σ (x – xbar)^2/n-1, what is required for the variance to equal zero?
Which best describes (x - xbar)^2: positive, non-positive, negative, or non-negative? Given that, is it even possible for the sum to equal zero? If so, under what conditions? How does that relate to whether the variance is zero?
 
In the formula for the variance of values in a sample, Σ (x – xbar)^2/(n-1), . . .


conniejoy,

you have to state/specify which kind of variance it is you want. Also, you must
put that binomial in grouping symbols when you type it out horizontally.


Population variance:


\(\displaystyle Σ (i = 1 \ \ to \ \ n) \ \) of \(\displaystyle \ \dfrac{(x_i \ \ – \ \ mu)^2}{n}, \ \ \ where \ \ "mu" \ \ is \ \ the \ \ population \ \ mean.\)



- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -


Sample variance:


\(\displaystyle Σ (i = 1 \ \ to \ \ n) \ \) of \(\displaystyle \ \dfrac{(x_i \ \ – \ \ xbar)^2}{n - 1}, \ \ \ where \ \ "xbar" \ \ is \ \ the \ \ sample\ \ mean.\)
 
Last edited:
Top