Probability

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safrey0940

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Apr 10, 2013
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3 of 6 people are to be selected and given a small prize. One will be given a book, one will be given gum, and one will be given candy. In how many different ways can each prize be awarded. My answer I came up with was 20. A couple of classmates are saying 120. I used the 6p3 and came up with 20.
 
safrey0940 said:
3 of 6 people are to be selected and given a small prize. One will be given a book, one will be given gum, and one will be given candy. In how many different ways can each prize be awarded. My answer I came up with was 20. A couple of classmates are saying 120. I used the 6p3 and came up with 20.
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Well \(\displaystyle _6\mathcal{P}_3=6\cdot 5\cdot 4=120\), so who is correct?
 
Not sure if I am using the right method to get the correct answer. My first answer was 120, but then I changed it to 20.
 
safrey0940 said:
Not sure if I am using the right method to get the correct answer. My first answer was 120, but then I changed it to 20.
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Well clearly you are incorrect there, \(\displaystyle n\ge k,~_n\mathcal{P}_k=\dfrac{n!}{(n-k)!}\)
 
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