easy probability

qcc said:

You have three fair coins. The first has a 0 on one side and a 1 on the other. The second has a 2 on one side and a 3 on the other, and the third has a 4 on one side and a 5 on the other. You flip the three coins and write down the numbers you see.
a) List all the outcomes for this experiment.

x-, 2,x.
I'm stressed out. How do I solve this?

Each coin can be either of 2 numbers so there are 2(2)(2)= 8 possible outcomes:
0-2-4
1-2-4
0-3-4
1-3-4
can you list the other four?

b) What is the probability that the sum of the numbers on the coins is 7?

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If the first coin is 0, the second number has to be 3 and the third number 4 in order to add up to 7.
If the first coin is 1, the other two numbers must add to 6 the second number must be 2 and the third number 4.

That is, out of the 8 (equally likely) outcomes, 2 of them sum to 7.

Click to expand...

Click to expand...

You have three fair coins.
The first has a 0 on one side and a 1 on the other,
the second has a 2 on one side and a 3 on the other,
and the third has a 4 on one side and a 5 on the other.
You flip the three coins and write down the numbers you see.

a) List all the outcomes for this experiment.

Click to expand...

b) What is the probability that the sum of the numbers is 7 ?

Click to expand...