SQRT(-x^2 + 8x - 11) = 12 - 2x
square both sides:
-x^2 + 8x - 11 = 144 - 48x + 4x^2
solve for x
If you don't know a certain word, then please MAKE SURE by yourself; we don't read minds.
And "u" is not a word: use YOU.
thnaks, and dont get mad im not familiar with mathemathic terms in english
Strictly speaking the word is "vinculum" but no one has used it for centuries! I would have said just "square root symbol" or "square root sign". In Latex you can use "\sqrt{-x^2+ 8x- 11}" which gives \(\displaystyle \sqrt{-x^2+ 8x- 11}= 12- 2x\).(-x2+8x-11) root=12-2x
above -x2+8x-11 there is root(i dont know if its the right word) line
You don't appear to have tried. Why not? As was suggested start by squaring both sides. Be careful, squaring both sides, like multiplying both sides by something involving x, may introduce "spurious roots" that satisfy the new equation but not the original one. Be sure to check any root in the original equation.the answer is x=5
thank u