About to loos my mind

Good afternoon this is my first time taking Algebra and I am stuck on a problem we were using our birthdates a is the month b is the date and c is the year.
this is how the problem is
(a-b) the b is negative that answer I got then the rest of the problem is (a2 +ab-b2) and I am stuck about solving this second half:neutral:

This is not a good question. It is not clear at all what is wanted. Please provide a better question.

agwhite said:

Good afternoon this is my first time taking Algebra and I am stuck on a problem we were using our birthdates a is the month b is the date and c is the year.
this is how the problem is
(a-b) the b is negative that answer I got then the rest of the problem is (a2 +ab-b2) and I am stuck about solving this second half:neutral:

Click to expand...

a = your birth month, b = day, c = year
You have already found a-b

In the second expression the digits "2" probably mean "squared":

\(\displaystyle \displaystyle a^2 + a*b - b^2\)

When typing inline we use the symbol "^" to mean "raised to the power":
a^2 + a*b - b^2

A squared number is multiplied by itself. Then the expression is the same as
a*a + a*b - b*b