probability

jms

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Aug 19, 2013
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Pretty please can samone help with this problem:

Some of the milk cans are leaking. 98% of them are not leaking. When the shop owner checks the condition of 30 milk cans what is the probability that he finds

a) two leaking milk cans
b) at least two leaking milk cans?

Apologies for the English, I tried to translate this from another language.
 
Some of the milk cans are leaking. 98% of them are not leaking. When the shop owner checks the condition of 30 milk cans what is the probability that he finds
a) two leaking milk cans
b) at least two leaking milk cans?

You must assume that this is binomial probability.

\(\displaystyle \mathcal{P}(X=k)=\dbinom{N}{k}(p)^k(1-p)^{N-k}\) is the probability of k happening out of N trials with probability p.

In your question \(\displaystyle N=30,~k=2,~\&~p=0.02\)

For b) \(\displaystyle 1-\mathcal{P}(X=0)-\mathcal{P}(X=1)\)
 
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