Algeb

kinuel8091

New member
Joined
Jul 27, 2013
Messages
24
How to answer this?qwewe.JPG


Well, I answered it already and this was the result. Is it right?
e.JPG
 
Hello, kinuel8091!

How to answer this?View attachment 3154


Well, I answered it already and this was the result. Is it right?
View attachment 3155

Your work is correct . . . so far.

It can be simplified.


Factor: .\(\displaystyle \dfrac{24(a-1)}{(a-2)(a+1)(a+5)(a-1)}\)

Reduce: .\(\displaystyle \dfrac{24(\color{red}{\rlap{/////}}a-1)}{(a-2)(a+1)(a+5)(\color{red}{\rlap{/////}}a-1)} \;=\;\dfrac{24}{(a-2)(a+1)(a+5)}\)
 
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