How to answer this? Well, I answered it already and this was the result. Is it right?
K kinuel8091 New member Joined Jul 27, 2013 Messages 24 Aug 25, 2013 #1 How to answer this? Well, I answered it already and this was the result. Is it right?
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Aug 25, 2013 #2 Hello, kinuel8091! How to answer this?View attachment 3154 Well, I answered it already and this was the result. Is it right? View attachment 3155 Click to expand... Your work is correct . . . so far. It can be simplified. Factor: .\(\displaystyle \dfrac{24(a-1)}{(a-2)(a+1)(a+5)(a-1)}\) Reduce: .\(\displaystyle \dfrac{24(\color{red}{\rlap{/////}}a-1)}{(a-2)(a+1)(a+5)(\color{red}{\rlap{/////}}a-1)} \;=\;\dfrac{24}{(a-2)(a+1)(a+5)}\)
Hello, kinuel8091! How to answer this?View attachment 3154 Well, I answered it already and this was the result. Is it right? View attachment 3155 Click to expand... Your work is correct . . . so far. It can be simplified. Factor: .\(\displaystyle \dfrac{24(a-1)}{(a-2)(a+1)(a+5)(a-1)}\) Reduce: .\(\displaystyle \dfrac{24(\color{red}{\rlap{/////}}a-1)}{(a-2)(a+1)(a+5)(\color{red}{\rlap{/////}}a-1)} \;=\;\dfrac{24}{(a-2)(a+1)(a+5)}\)