Since last two digits take up 2 & 1 and there is no repetition - we need to make four digit numbers from remaining 8 numbers.
We can fill the left most digit 7 numbers (cannot have zero in the left most digit)
We can fill the next position with 7 numbers (one number used at front but 0 is back in play)
We can fill the next position with 6 numbers....
We can fill the next position with 5 numbers....
Now what.....
Please share your work with us .
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