Hi,
I need help solving this problem
About o.1% of people in a given population carry a disease. For those that carry the disease, test are positive in 98% of cases. For those that do not carry the disease, tests are negative 94% of the time.
Given that a person rests positive, what is the probability that the person carries the disease?
p(disease)=0.01%
P(carry disease|test positive)= 98%
P(do not carry|test negative)=94%
P(carry disease[FONT=MathJax_Main]∩[/FONT] test positive) = P(disease) * P(carry disease|test positive)
= (0.0001)(0.98)
but what do I do with the last piece of information (P(do not carry|test negative)=94%) why is that there?
Thanks
I need help solving this problem
About o.1% of people in a given population carry a disease. For those that carry the disease, test are positive in 98% of cases. For those that do not carry the disease, tests are negative 94% of the time.
Given that a person rests positive, what is the probability that the person carries the disease?
p(disease)=0.01%
P(carry disease|test positive)= 98%
P(do not carry|test negative)=94%
P(carry disease[FONT=MathJax_Main]∩[/FONT] test positive) = P(disease) * P(carry disease|test positive)
= (0.0001)(0.98)
but what do I do with the last piece of information (P(do not carry|test negative)=94%) why is that there?
Thanks