Yes, that gives me x=2. What about the other side which apparently gives x=3/4?
I have no idea what you are doing because you are not showing your work.
Do you understand the zero property concept behind solving a quadratic by factoring?
Let's take an example
\(\displaystyle x^2 - x - 42 = 0.\)
I can factor that equation so that it becomes
a product of two linear terms.
\(\displaystyle x^2 - x - 42 = 0 \implies (x - 7)(x + 6) = 0.\) Does that make sense to you?
If a * b = 0, then either a = 0 or b = 0 or a = b = 0. This is the zero product property. So let's apply it to the equation in the line above.
\(\displaystyle (x - 7)(x + 6) = 0 \implies x - 7 = 0\ or\ x + 6 = 0 \implies x = 7\ or\ x = - 6.\)
Now as far as I can see you have not reduced your quadratic to a simple product of two linear terms. Try doing that and then applying the zero product property.
By the way, this zero product property is a way to find the zeroes of polynomials with a higher degree than 2 such as cubics, quartics, qunitics, etc. So it is a useful technique to learn, but you never have to use it with quadratics.