Statistics Problem Help!!

P(1) = 0.054 is correct.

In Pick 3, a) 1000 different selections is correct
b) then the chance of winning should be one out of 1000
c) Profit = $490.69 is correct
d) Expected value is probability × Profit

4 tires randomly selected...
a) 1st probability = 6080/6300; 2nd 6079/6299; 3rd 6078/6295; 4th 6077/6294
........To 3 decimal places, the result is the same as using p=6080/6300 four times
b) How did you get 0.016 as P(100 all good)? It looks like a good result.

Those are the only ones I could see that you had tried. Please show your work!
 
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