prettylittlepixels
New member
- Joined
- Nov 15, 2013
- Messages
- 32
Begin by finding the value of k that will make the following a probability function:
P(x) = {[(x/2) + 3]^2} / 19k for x = 2, 4, 6, 8, 10
I have several questions to solve using this equation and want to be sure I solve for k properly before making a lot of incorrect calculations on the incorrect value of k.
I'm not sure where to begin with this problem. When I substitute 2 in for the x-value, I end up with 16/19k and if I multiply by k, I get 16/19, which is rounded to 0.84.
Is this right?
Substituting 4 in as the x-value gives me 25/19k, which is completely different. What am I missing?
Thanks in advance?
P(x) = {[(x/2) + 3]^2} / 19k for x = 2, 4, 6, 8, 10
I have several questions to solve using this equation and want to be sure I solve for k properly before making a lot of incorrect calculations on the incorrect value of k.
I'm not sure where to begin with this problem. When I substitute 2 in for the x-value, I end up with 16/19k and if I multiply by k, I get 16/19, which is rounded to 0.84.
Is this right?
Substituting 4 in as the x-value gives me 25/19k, which is completely different. What am I missing?
Thanks in advance?