champion123
New member
- Joined
- Jan 9, 2014
- Messages
- 1
Hi there, I am confused on the following problem and need help from someone strong at maths
Suppose there are 100 horse races per day and 6 horse racing per race. The horses are in the order of the 1st favourite (highest rated horse) to the 6th favourite (Least rated horse). The probability of the 6th fav winning is 5% (0.05) and the 5th fav winning is 6% (0.06)
Therefore I understood that the probability of 2 6th fav winning one after another in a row is 0.25% (0.05*0.05) and 2 5th fav winning is 0.36% (0.06*0.06)
Question is, what is the probability that you will see both 2 consecutive 6th fav winners and 2 consecutive 5th fav winners in a day race? I suppose the answer is not derived from 0.25*0.36? As the probability seems too small to be correct
Suppose there are 100 horse races per day and 6 horse racing per race. The horses are in the order of the 1st favourite (highest rated horse) to the 6th favourite (Least rated horse). The probability of the 6th fav winning is 5% (0.05) and the 5th fav winning is 6% (0.06)
Therefore I understood that the probability of 2 6th fav winning one after another in a row is 0.25% (0.05*0.05) and 2 5th fav winning is 0.36% (0.06*0.06)
Question is, what is the probability that you will see both 2 consecutive 6th fav winners and 2 consecutive 5th fav winners in a day race? I suppose the answer is not derived from 0.25*0.36? As the probability seems too small to be correct