Binomial distribution question. please help me! thank you very much!

qwert

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A company distributed a large number of lucky draw tickets to their customers. It is known that 20% of the tickets are winning tickets which can be exchanged for a prize. Each customer is entitled to only one lucky draw ticket.

(i) A group of 15 customers is randomly chosen. Show that the probability that at least 3 customers will each win a prize is 0.602.
Hence, find the probability that at most 5 customers will each win a prize given that at least 3 customers will each win a price.

Thank you very much! I've found 0.602 but I have 0 idea for the hence part of the question.


 
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