‘The line L has gradient -2 and passes through the point A (3,5). B is a point of the line L such that the distance AB is 6√5. Find thecoordinates of each of the possible points B’.
So I first calculated the equation of L…
Y - Y₁ = m (X - X₁)
Y – 5 = -2 (X – 3)
Y – 5 = -2X + 6
Y = 11 – 2X
So I then drew a triangle to try and visualise the problem---and I got …
(X – 3)² + (Y – 5)² = (6√5)²
Giving … X² + Y² - 6X – 10Y = 146
However I have no clue what I should do with this or withthe equation of L, somebody pointing me towards the next step would be muchappreciated J. Cheers.
So I first calculated the equation of L…
Y - Y₁ = m (X - X₁)
Y – 5 = -2 (X – 3)
Y – 5 = -2X + 6
Y = 11 – 2X
So I then drew a triangle to try and visualise the problem---and I got …
(X – 3)² + (Y – 5)² = (6√5)²
Giving … X² + Y² - 6X – 10Y = 146
However I have no clue what I should do with this or withthe equation of L, somebody pointing me towards the next step would be muchappreciated J. Cheers.