2/3(2-3x)=5
Is the above meant to be one of the following?I have tried 3 times and got 3 different answers
2/3(2-3x)=5
What do you need to find?
Since you tried 3-times - share at least one of those attempts.
2/3(2-3x)=5 \(\displaystyle \ \ \ \ \)To be clear, you should put the fraction in grouping symbols.
4/3-6x/3=5
4/3-2x=5
-2x=5-4/3
-2x=-11/3\(\displaystyle \ \ \ \ \)The sign of the fraction is wrong.
x=-11/3*1/2\(\displaystyle \ \ \ \ \)When you multiplied by the reciprocal, you didn't include the negative sign.
x=-11/6\(\displaystyle \ \ \ \ \) Your two errors above cancelled each out. This happens to be the correct answer.
So, it was, in fact, (2/3)(2- 3x)= 5, not 2/(3(2x- ))= 5?2/3(2-3x)=5
4/3-6x/3=5
Here is your error. 5- 4/3= 15/3- 4/3= (15- 4)/3= 11/3, not -11/3.4/3-2x=5
-2x=5-4/3
-2x=-11/3
x=-11/3*1/2
x=-11/6
Get rid of fraction; multiply by 3:
2(2 - 3x) = 15
4 - 6x = 15
-6x = 11
x = -6/11
Remember that...useful on a "timed test"...
Denis,
you goofed at the end.
It's supposed to be
"x = -11/6"