Mathimatician
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- Mar 24, 2015
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A litter of 6 puppies, 3 male and 3 female, is being sold to friendly homes. What is the probability that the first and last puppies sold will be male?
This is my solution:
(4!/3!)/(6!/(3!3!)) = 1/5
the (4!/3!) is the number of ways that you can order the middle 4 puppies assuming that you have a male at front and back (4 puppies to order but 3 are identical).
then the (6!/(3!3!)) is the total number of ways the puppies can be sold.
is this correct?
This is my solution:
(4!/3!)/(6!/(3!3!)) = 1/5
the (4!/3!) is the number of ways that you can order the middle 4 puppies assuming that you have a male at front and back (4 puppies to order but 3 are identical).
then the (6!/(3!3!)) is the total number of ways the puppies can be sold.
is this correct?
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