Superwoman
New member
- Joined
- Mar 14, 2015
- Messages
- 3
Hi! Can anybody help with the following problem?
Rules for the 'who want to be a Millionaire'
One must reply to 8 - very difficult - questions on general knowledge. For each question is given 4 possible answers. When all 8 questions are answered, the following prizes are earned:
At 8 correct answers: 1000 times the bet back
At 7 correct answers: 100 times the bet back
At 6 correct answers: 10 times the bet back
The probability of profit increases if the girl knows one or more of the correct answers. Assume that the girl necessarily knows ONE correct answer every time she plays.
If the girl could afford to play a large number of times, what is her average win / loss. Suppose she rates $100. Each time and is always sure of ONE question?
Is it supposed to be solved like this?:
(7*1000)*100= x
(6*100)*100= y
(5*10)*100= z
x + y + z = average win/loss?
I was thinking, that as she always knows one of the answers and have to guess on the rest. The numbers 8, 7 and 6 should therefore be changed to 7, 6 and 5. Then I could multiply the probability of getting 7 correct answers with 1000 (the prize) which would then again be multiplied with the $100 that is spend. I would then do this with 6 and 5 as well, and add the results to get the average win/loss?
Rules for the 'who want to be a Millionaire'
One must reply to 8 - very difficult - questions on general knowledge. For each question is given 4 possible answers. When all 8 questions are answered, the following prizes are earned:
At 8 correct answers: 1000 times the bet back
At 7 correct answers: 100 times the bet back
At 6 correct answers: 10 times the bet back
The probability of profit increases if the girl knows one or more of the correct answers. Assume that the girl necessarily knows ONE correct answer every time she plays.
If the girl could afford to play a large number of times, what is her average win / loss. Suppose she rates $100. Each time and is always sure of ONE question?
Is it supposed to be solved like this?:
(7*1000)*100= x
(6*100)*100= y
(5*10)*100= z
x + y + z = average win/loss?
I was thinking, that as she always knows one of the answers and have to guess on the rest. The numbers 8, 7 and 6 should therefore be changed to 7, 6 and 5. Then I could multiply the probability of getting 7 correct answers with 1000 (the prize) which would then again be multiplied with the $100 that is spend. I would then do this with 6 and 5 as well, and add the results to get the average win/loss?