Hi, I need help! I am new btw

Mellie

New member
Joined
Apr 26, 2015
Messages
2
A point
e53b1fe25be1c679117fb44a6a886fe1247d189a.png
is randomly selected such that
e60c26a5726e3803b17a4625ca994107243a7814.png
and
d03ee994abb7a100e4575e3c838c700c09f831ff.png
. What is the probability that
02fe7d4fbd4eee46d62e27cf147d6978f730b4ff.png
? Express your answer as a common fraction.

 
This can be done using areas. The probability is calculated as the ratio of two areas.

All points with x-coordinate from 0 to 8 and y-coordinate from 0 to 4 form a simple shape (rectangle). Its lower-left corner is positioned at the origin. Draw it on a graph.

Within this rectangular region, all of the points lying below the line x+y=4 also form a simple shape (triangle). To see it, plot the line through the rectangle on your graph.

Calculate the area of the rectangular region.

Calculate the area of the triangular region.

The probability is the ratio of the smaller region to the larger.

Questions? :cool:
 
This can be done using areas. The probability is calculated as the ratio of two areas.

All points with x-coordinate from 0 to 8 and y-coordinate from 0 to 4 form a simple shape (rectangle). Its lower-left corner is positioned at the origin. Draw it on a graph.

Within this rectangular region, all of the points lying below the line x+y=4 also form a simple shape (triangle). To see it, plot the line through the rectangle on your graph.

Calculate the area of the rectangular region.

Calculate the area of the triangular region.

The probability is the ratio of the smaller region to the larger.

Questions? :cool:

I like the way you provide hints.....
 
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