lbr
New member
- Joined
- Aug 27, 2015
- Messages
- 3
Hello!
It's the first time I'm posting here and I'm a pretty big pleb at math.
\(\displaystyle 1c.\, \dfrac{\dfrac{4}{5}\, -\, \dfrac{2}{25}}{\dfrac{1}{10}\, -\, \dfrac{3}{5}}\, =\, \dfrac{\dfrac{4}{5}\, \cdot\, \dfrac{10}{10}\, -\, \dfrac{2}{25}\, \cdot\, \dfrac{2}{2}}{\dfrac{1}{10}\, \cdot\, \dfrac{5}{5}\, -\, \dfrac{3}{5}\, \cdot\, \dfrac{10}{10}}\, =\, \dfrac{\dfrac{40}{50}\, -\, \dfrac{4}{50}}{\dfrac{5}{50}\, -\, \dfrac{30}{50}}\)
\(\displaystyle =\, \dfrac{40\, -\, 4}{50}\, \cdot\, \dfrac{50}{5\, -\, 30}\, =\, \dfrac{40\, -\, 4}{5\, -\, 30}\)
\(\displaystyle e. \dfrac{\dfrac{3x}{2}\, -\, \dfrac{15}{4}}{\dfrac{3x}{5}\, +\, \dfrac{3}{2}}\, =\, \dfrac{\dfrac{3x}{2}\, \cdot\, \dfrac{10}{10}\, -\, \dfrac{15}{4}\, \cdot\, \dfrac{5}{5}}{\dfrac{3x}{5}\, \cdot\, \dfrac{4}{4}\, +\, \dfrac{3}{2}\, \cdot\, \dfrac{10}{10}}\, =\, \dfrac{\dfrac{30x}{20}\, -\, \dfrac{75}{20}}{\dfrac{12x}{20}\, +\, \dfrac{30}{20}}\)
\(\displaystyle =\, \dfrac{\dfrac{30x\, -\, 75}{20}}{\dfrac{12x\, -\, 30}{20}}\, =\, \dfrac{30x\, -\, 75}{12x\, -\, 30}\)
\(\displaystyle =\, \dfrac{30x\, -\, 12x}{+75\, -\, 30}\, =\, \dfrac{18x}{35}\)
Could you help me?
It's the first time I'm posting here and I'm a pretty big pleb at math.
\(\displaystyle 1c.\, \dfrac{\dfrac{4}{5}\, -\, \dfrac{2}{25}}{\dfrac{1}{10}\, -\, \dfrac{3}{5}}\, =\, \dfrac{\dfrac{4}{5}\, \cdot\, \dfrac{10}{10}\, -\, \dfrac{2}{25}\, \cdot\, \dfrac{2}{2}}{\dfrac{1}{10}\, \cdot\, \dfrac{5}{5}\, -\, \dfrac{3}{5}\, \cdot\, \dfrac{10}{10}}\, =\, \dfrac{\dfrac{40}{50}\, -\, \dfrac{4}{50}}{\dfrac{5}{50}\, -\, \dfrac{30}{50}}\)
\(\displaystyle =\, \dfrac{40\, -\, 4}{50}\, \cdot\, \dfrac{50}{5\, -\, 30}\, =\, \dfrac{40\, -\, 4}{5\, -\, 30}\)
\(\displaystyle e. \dfrac{\dfrac{3x}{2}\, -\, \dfrac{15}{4}}{\dfrac{3x}{5}\, +\, \dfrac{3}{2}}\, =\, \dfrac{\dfrac{3x}{2}\, \cdot\, \dfrac{10}{10}\, -\, \dfrac{15}{4}\, \cdot\, \dfrac{5}{5}}{\dfrac{3x}{5}\, \cdot\, \dfrac{4}{4}\, +\, \dfrac{3}{2}\, \cdot\, \dfrac{10}{10}}\, =\, \dfrac{\dfrac{30x}{20}\, -\, \dfrac{75}{20}}{\dfrac{12x}{20}\, +\, \dfrac{30}{20}}\)
\(\displaystyle =\, \dfrac{\dfrac{30x\, -\, 75}{20}}{\dfrac{12x\, -\, 30}{20}}\, =\, \dfrac{30x\, -\, 75}{12x\, -\, 30}\)
\(\displaystyle =\, \dfrac{30x\, -\, 12x}{+75\, -\, 30}\, =\, \dfrac{18x}{35}\)
Could you help me?
Attachments
Last edited by a moderator: