xclusive229
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- Sep 17, 2015
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I recently conducted some animal research where I was investigating survival of swine based on what drug was given to them. Data are shown below.
a. Let Ai represent the drug provided: A1 is drug 1, A2 is drug 2. Let Bi represent the pig's survival: B1 indicates that the animal survived, and B2 indicates that it died. For each cell in the table below, calculate the joint probability. In other words, calculate P(A1 B1), P(A1 B2), P(A2 B1), and P(A2 B2). Place these probabilities in the following table. (Don't panic here. This is as easy as you think it is.)
b. For each row and column, calculate the marginal probability. In other words, calculate the four marginal probabilities, P(A1), P(A2), P(B1), and P(B2). Place them in the next table with the results from part a. (Just remember how we calculated marginal probability in class.)
**Are these parts correct?**
Survived | Died | Totals | |
Drug 1 | 7 | 0 | 7 |
Drug 2 | 5 | 2 | 7 |
Totals | 12 | 2 | 14 |
a. Let Ai represent the drug provided: A1 is drug 1, A2 is drug 2. Let Bi represent the pig's survival: B1 indicates that the animal survived, and B2 indicates that it died. For each cell in the table below, calculate the joint probability. In other words, calculate P(A1 B1), P(A1 B2), P(A2 B1), and P(A2 B2). Place these probabilities in the following table. (Don't panic here. This is as easy as you think it is.)
Survived | Died | |
Drug 1 | 35 | 14 |
Drug 2 | 0 | 0 |
b. For each row and column, calculate the marginal probability. In other words, calculate the four marginal probabilities, P(A1), P(A2), P(B1), and P(B2). Place them in the next table with the results from part a. (Just remember how we calculated marginal probability in class.)
Survived | Died | Totals | |
Drug 1 | 7/7 | 0/7 | 7/14 |
Drug 2 | 5/7 | 2/7 | 7/14 |
Totals | 12/14 | 2/14 | 14/14 |
**Are these parts correct?**
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