Probability Question: Given that 30% of employed persons are in favour of...

Given that 30% of employed persons are in favour of the implementation of the flexi- week, in a sample of 20 employed persons calculate the following probabilities: a) More than 17 workers are in favour of the flexi-week..... b) Only 10 workers support the flexi-week .....c) Less than 3 persons are in favour of the flexi-week .....d)Also determine the numbers of persons in the sample who are expected to be in favour of the flexi-week as well as the variance

EclipseWhisper said:

Given that 30% of employed persons are in favour of the implementation of the flexi- week, in a sample of 20 employed persons calculate the following probabilities: a) More than 17 workers are in favour of the flexi-week..... b) Only 10 workers support the flexi-week .....c) Less than 3 persons are in favour of the flexi-week .....d)Also determine the numbers of persons in the sample who are expected to be in favour of the flexi-week as well as the variance

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What are your thoughts?

Please share your work with us ...even if you know it is wrong

If you are stuck at the beginning tell us and we'll start with the definitions.

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Subhotosh Khan said:

What are your thoughts?

Please share your work with us ...even if you know it is wrong

If you are stuck at the beginning tell us and we'll start with the definitions.

You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL:

http://www.freemathhelp.com/forum/th...Before-Posting

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..... Can anyone help me??

Yes, we certainly can help you. But that's the key word - help. Generally, the student provides their efforts and we give hints. However, since, even after being asked to do so, you've shown no work, I must assume you are stuck at the very beginning.

So, you're told that 30% of workers at this company support a flexi-week work schedule. However, you don't know if any of the 20 workers surveyed are part of that 30% that favor the flexi-week. Given that, what do you suppose the probability of any one worker supporting the flexi-week? And then you also know the probability of any one worker not supporting the flexi-work. Now let's tackle part b, since that seems easiest to me. You need to find the probability of exactly 10 workers supporting the flexi-week. Given the probability of one worker supporting it, can you calculate the probability of two supporting it? Three workers? And so on, working your way up to 10.

That should get you started on your way. If you get stuck again, that's okay. But you have to be willing to work with us and show us how far you got. We give help, not answers.