I'm having the hardest time using the inverse transform method to determine the continuous process generator for this probability distribution. Can anyone help me out? Thanks.
\(\displaystyle f(t)\, =\, \begin{cases}\dfrac{t^{-1/2}}{6}&\mbox{for }\, 0\, <\, t\, <\, 9\\\,&\,\\\,0&\mbox{elsewhere}\end{cases}\)
\(\displaystyle f(t)\, =\, \begin{cases}\dfrac{t^{-1/2}}{6}&\mbox{for }\, 0\, <\, t\, <\, 9\\\,&\,\\\,0&\mbox{elsewhere}\end{cases}\)
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