Sorry, but the policy you saw in the "Read Before Posting" announcement remains in effect; namely, we don't "do" students' work for them, nor do we provide complete solutions. Students still need to show some effort of their own.Can I have a detailed proof please
What you have posted means the following:If X/a-b+c = Y/b-c+a = Z/c-a+b
Prove that : X+Y/a = Y+Z/b
First the answer is absolutely not.Can I have a detailed proof please
If X/a-b+c = Y/b-c+a = Z/c-a+b
Prove that : X+Y/a = Y+Z/b
Oh, I didn't mean I need a complete work.. I wanted a complete proof to help me understand how this is made.Sorry, but the policy you saw in the "Read Before Posting" announcement remains in effect; namely, we don't "do" students' work for them, nor do we provide complete solutions. Students still need to show some effort of their own.
What you have posted means the following:
. . . . .\(\displaystyle \mbox{If }\, \dfrac{X}{a}\, -\, b\, +\, c\, =\, \dfrac{Y}{b}\, -\, c\, +\, a\, =\, \dfrac{Z}{c}\, -\, a\, +\, b,\)
. . . . .\(\displaystyle \mbox{then prove that }\, X\, +\, \dfrac{Y}{a}\, =\, Y\, +\, \dfrac{Z}{b}\)
Was this what you meant?
When you reply, please include a clear listing of your thoughts and working so far. Thank you!
I'm sorry, but what is the difference between "a complete work" and "a complete proof" of the work, especially since "the work" is exactly "the proof"? :shock:Oh, I didn't mean I need a complete work.. I wanted a complete proof to help me understand how this is made.
Besides, I don't really know how you wrote the equation this way but that isn't what I meant.
I meant that the whole part after the (/) sign was the denominator. for example (X/a-b+c) X is the numerator and a-b+c is the denominator.