4x^2+9y^2 = 12xy

J

jejo1

New member
Joined
Feb 9, 2016
Messages
6
4X^2+9Y^2 = 12XY
{(X varies as 1/Y) , (X varies as y) , (X varies as 2/3 Y) , (X = 2/3Y)}

I think the answer to the equation is x/y = 3/2
but I'm not sure what type of variation is it
 
jejo1 said:
4X^2+9Y^2 = 12XY
{(X varies as 1/Y) , (X varies as y) , (X varies as 2/3 Y) , (X = 2/3Y)}

I think the answer to the equation is x/y = 3/2
but I'm not sure what type of variation is it
Click to expand...
What is the full text of the exercise? What were the instructions? What is the meaning of the "set" (?) within the curly braces?

When you reply, please include a clear statement of why you "think the answer to the equation" is the specified rational equation, and why you feel that "type of variation" might be relevant. Thank you! ;)
 
jejo1 said:
4X^2+9Y^2 = 12XY
{(X varies as 1/Y) , (X varies as y) , (X varies as 2/3 Y) , (X = 2/3Y)}

I think the answer to the equation is x/y = 3/2
but I'm not sure what type of variation is it
Click to expand...

4X^2+9Y^2 = 12XY

4X^2+9Y^2 - 12XY = 0

(2*X - 3*Y)^2 = 0

2*X - 3*Y = 0 ..................... so you are correct that the equation actually is X/Y = 3/2

Y = 2/3 * X ........................... What kind of variation is this?
 
Subhotosh Khan said:
4X^2+9Y^2 = 12XY

4X^2+9Y^2 - 12XY = 0

(2*X - 3*Y)^2 = 0

2*X - 3*Y = 0 ..................... so you are correct that the equation actually is X/Y = 3/2

Y = 2/3 * X ........................... What kind of variation is this?
Click to expand...

Direct variation...
 
You must log in or register to reply here.
Top