Probability that a number matches a partially hidden coded number

MarkIngs

New member
Joined
Jul 16, 2016
Messages
2
Let's say I have a code for numbers made from a 4 x 4 matrix such that two letters match a number e.g.

ABCD
A1234
B5678
C90+-
DX/=.

I create a string of numbers using the code and hide them in the letters.

AA DD AD AA AD AB AA AC BA BB AB AC BC

The problem is, the code has become corrupted and now reads:

AA DD CD AA AD AD CA AC BA BB DB DC BC

A friend knows that the code has been corrupted, but makes some very good guesses at what might have been the 13 position number with seven number positions identified.

1.#14##356##7

What is the probability that my friend correctly guessed the 7 numbers and decimal? Secondly, given my friends result, what's the probability that the original number encoded was the square route of 2 (1.41421356237)?

It's unusual that one would be attempting to compare a number fragment to a larger reference number. Can you still multiply the probabilities of individual positions? In this case it would appear to be 1/4 chance of getting a letter correct, but 1/16 probability of correctly getting any one number.

Am I correct to assume that the probability of matching the 7 numbers and decimal is 1/16^8? Is there a general formula for working out such problems?
 
Last edited:
Clarification on corrupted code

So that string of yours represents these 13 characters:
1.x1x51926590

Is that correct?

Regardless, your problem statement makes no sense to me...
Can you be clearer?
WHY are you including + - x / = . :confused:

Apologies for any confusion. The matrix allows for the operators too, but these are not included in the problem.

The uncorrupted code with the 7 numbers guessed would look like

1 . AD 1 4 AB AA 3 5 6 AB AC 7

However, a result of code corruption it now looks like

1 . CD 1 4 AD CA 3 5 6 DB DC 7



It is known that the code has been corrupted and I'm trying to establish the probability of having correctly guessed the 7 numbers & decimal on the partially decoded number.
 
Last edited:
Top