The six faces of dice are numbered 1 to 6. Tw dice are dropped on the table
- Thread starter lishar
- Start date
D
Deleted member 4993
Guest
pka
Elite Member
- Joined
- Jan 29, 2005
- Messages
- 11,971
There are serious problems with the wording with the wording of this question.
Two dice dropped onto a table will show a sum of \(\displaystyle 2,~3,\cdots,11,~12\). So \(\displaystyle 35\) makes no sense.
If you do mean product then we have \(\displaystyle 1,~2,~3,~4,~5,~6,~8,~9,~10,~12,15,~16,~18,~20,~24,~25,~30,~36\) still no \(\displaystyle 35\).
Are you making a translation? Please correct the wording/
pka
Elite Member
- Joined
- Jan 29, 2005
- Messages
- 11,971
Well, thank you. I should never have guessed that was what that puzzle meant.
The sum of the numbers on a die is twenty-one.
So the sums of any five sides are: 15, 16, 17, 18, 19, 20. Rolling two dice the sums are 30 to 40.
Looking at this expansion, we see that there are thirty-six ways to get these sums. Six of those result in thirty-five.