Assume a lotto draw of 6 out of 49 different numbers (1 to 49). Every how many draws,

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harry.petrone

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[FONT=&quot]Assume a lotto draw of 6 out of 49 different numbers (1 to 49). [/FONT][FONT=&quot]Every how many draws, on average, the 6 winning numbers contain at least one pair of consecutive numbers? [/FONT]
 
harry.petrone said:
Assume a lotto draw of 6 out of 49 different numbers (1 to 49). Every how many draws, on average, the 6 winning numbers contain at least one pair of consecutive numbers?
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What are your thoughts?

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Lotto

Subhotosh Khan said:
What are your thoughts?

Please share your work with us ...even if you know it is wrong.

If you are stuck at the beginning tell us and we'll start with the definitions.

You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL:

http://www.freemathhelp.com/forum/announcement.php?f=33
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I am not sure: Total ways to choose 6 numbers from 49 - no restrictions is 49 C 6 = 13983816.
Within the 49 numbers, there are 48 pairs of 2 consecutive numbers.
There are 49 C 2 = 1176 ways to select exactly one pair out of 49 numbers.

So maybe the requested is 48/1176? So every 24,5 draws we get one pair?
 
Lotto

Denis said:
What do you consider one pair of consecutive numbers?
12,23,34,45
Also 10,21,32,43 ?
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Apologies, I did not express it correctly. I just meant "at least two consecutive numbers".
For example, 6, 7, 11, 34, 36, 44 (the "pair" is 6, 7).
 
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