V=(9, 5), (6, 5)

W=(2, 8), (7, 9)

x=(5, 1)

I have tried to work with the inverse och w, v back and forth but cant figure it out. please help, Thank you! ]]>

Math.jpg

It would be great if you could help me doing one or two.Have a good day!

nanana

x0=1

x(n+1)=2x(n)+1

S(n)=x0+x1+...x(n)

Find S(2018)

How do I find it?

I know that the terms are:x0=1,x1=3,x2=7,x3=15 and that the difference of the terms is 2,4,8 but how does that help me to find the formula for the sequence x(n)? ]]>

x²+10x=-8

My solution is ±√(17) -5

If however I try to "plug in" my solution into the original equation, I am told that it is not a true statement.

[±√(17) -5]²+10[±√(17) -5]=-8

My humblest gratitude for any assistance. Everything else about quadratics has made sense to me. This is the first time that the "checking" phase is what is stumping me :-?:confused:

]]>

I'm asked to find the range of this function:

Capture.jpg

It's easy to find the range if you are provided a graph, or if you are allowed to use a graphing calculator.

But I'd have to draw graphs by hand in final exam.

I've not been taught yet how to find minimums and maximums.

So,

The range of the function is

Capture 1.PNG

and (4.868, 499.82) is the maximum point (I hope I'm using the correct term here).

Find Eigen Values and Vectors for the matrix

Screen Shot 2018-12-15 at 11.40.22 AM.png

IMG_20181215_110807.jpg

IMG_20181215_110847.jpg

Is this correct? Can I have O as my eigen vector? This means that my origin does not get rotated of its axis after the transformation of the plane, right?

1) (7/10)x + y <= 630

2) (1/2)x + (5/6)y <= 600

3) x + (2/3)y <= 700

4) (1/10)x + (1/4)y <=135

I've simplified each equation to just be a y<= inequality and graphed it out on my TI84, but don't see an intersection point that indicates where the max value should be. I found elsewhere that the answer is (540, 252), but can't see how they got there.

Any help is appreciated. ]]>

maths1.jpgmaths 2.jpg

It states you can generate a decagon by using r = cos( 1+sqrt(theta)) as below.

When i try this equation in graph plotter i dont get it. What am i doing wrong?

decagon.jpg

in algebraic form. I can get the correct answer by changing

into exp form then applying the power then changing back

however the answer provided is -2^39(1-i*sqrt(3)). So I’m

looking for the way in which I come to this answer ]]>

problem.PNG

Here is book solution:

solution.PNG

Here is what I did:

mysolution.jpg

I know how to reduce this sort of expression when the exponent of something in the radicand is the same as the index or greater. But...how do you reduce something where the exponent is 2 and the index is 4? Now, I know that this is true because I checked it on a calculator. And I think I found that any time there is an exponent of 2 and an index of 4 you can subtract the lesser from the greater and result will be the new exponent of that element of the radicand. BUT: Try this with and exponent of 2 and an index of 5 and truth will forsake your results.

So, I am asking: How did the author get from the fourth root of 15^2 to the square root of 15?

I have simplified this logarithmic function:

h(x)=0.25*log_2 ((8x-56)^(16)) - 12

to

g(x) = 4*log_2 (x-7)

These are equivalent functions. I need to prove that via graphing.

However, when I graph the original function (h(x)), I get something of a "V".

Whereas, g(x) gives me the characteristic graph of log functions.

Graphing

My question is, what domain restrictions must I apply to h(x) for its graph to appear as g(x)'s?

Also, please kindly explain why does this happen? Are equivalent functions not

Thank you very much for your time. ]]>

I also need help with one of these. The rest of the problems I can handle on my own. Thank you.

Does anyone know how to do this? It'd be a great help, thankyou.