For regular APR calculation, I use Newton's method and the partial derivative of that function.

However, I now need to be able to calculate APR for biweekly payments, but I don't know what function to use or how to get the APR.

Examples below using the payment calculator from the Treasury Web site (no source code there).

Loan $2,995

Interest 14.99

Payment 125

Number of payments 26

Unit 14 days

1st Payment made 1 unit and 7 days out

Last payment made 26 units and...

Calculating APR for biweekly payments]]>

Thank you.]]>

Can someone show me how to start this? So far I got p=25, and k=15, but I am not sure about the other symbol...as I cannot find that in my calculator not the factorial symbol but the reversed v symbol. Can anyone help? Thanks.]]>

a) The last month Emma will...

Solve using calculus]]>

If 6 workers complete 8 tasks in 4 hours how many workers would it take to complete 12 tasks in 2 hours. My answer is 15.

The way i solved it was by adding 6 more workers to the first problem reducing the completion time to 2 hours then if i add the 4 to 8 which is only half the original task load to keep the hours at 2 i only needed to add half of the amount of...

Quick help on an easy solve.]]>

"Hey, bug on my back, are you a mite?" the fly asks.

"I mite be," giggles the mite.

"That's the worst pun I've ever heard," groans the fly.

"What do you expect?" says the mite. "I came up with it on the fly."]]>

Evaluate this limit: \(\displaystyle \lim_{x\to 0} \left(\frac{\sqrt{1+\sin^2 x^2} - \cos^3 x^2}{x^3 \tan x}\right)\)

So, i decided to try and answer the problem. After a few hours, i've found a solution for it, but i feel a bit unsure. Here's my solution:

\(\displaystyle \rightarrow\) Using L'Hopital's rule,

=\(\displaystyle \lim_{x\to 0} \left(\frac{\frac{2x\sin x^2\cos...\)

A math competition problem (Limits)]]>

I would like to know if the method I’m using to calculate a probability based on an occurrence rate is correct or if there is a better method to use.

Probability given an occurrence rate (small airplane fatal accidents)]]>

Weirdd Statistics problem]]>

They have decided to split the award as follows:

(i) Arden receives $10 000 plus 1/5 of what then remains;

(ii) Dale then receives $16 000 plus 1/4 of what then remains; and

(iii) Ryan then receives the rest, which is $18 000. How much is the original monetary award?

Which co-worker receives the most money?]]>

I think it's because both trigonometric ratios use the hypotenuse plus either the adjacent or opposite side. The subtraction part plays a role by subtracting the bigger adjacent/opposite side.

Of course, I know that sin(x) = cos(90−x) because I punched it in the calculator, but I'm getting frustrated and am struggling to understand why. Can someone please better explain it to me with loads of details but simple?]]>

I left the two terms separate cause I figured the Algebra needed to combine the two wasn't worth it considering my upper and lower bounds were [-1,1]. Therefore (pending my antiderivative is correct) I can plug in my bounds which will eliminate the powers since 1 to any power will be 1. Then it is just a matter of summing the fractions.]]>

I have defined h and θ in the image. θ is the angle between the vertical and the tangent line at a given point. h is the vertical distance from the beginning of the cycloid to the given point.

Thanks,

Ardalan

]]>

Using the Fundamental Theorem of Calculus I found the antiderivative of the integrand. Then I found the difference of the upper and lower bound values inserted into the antiderivative.

I double checked the work both logically with the integral/antiderivative relationship and through symbolab so all should be well. But I wanted to double check and get feedback.]]>

How much do you have at the end of 40 years?

Using the Financial Calculator I used these inputs:

PV = 0

PMT = 1095 (3*365)

N = 40

I/Y = 11%

My FV = 637,099.54.

I feel like I should be including leap years which would have added an extra $3 on 10 separate occasions. Any help with these...

Time Value Money]]>