Home
Forums
New posts
Search forums
What's new
New posts
Latest activity
Log in
Register
What's new
Search
Search
Everywhere
Threads
This forum
Search titles only
By:
New posts
Search forums
Menu
Log in
Register
Install the app
Install
Forums
Free Math Help
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Intermediate/Advanced Algebra
For more advanced algebra topics, including Algebra II and Pre-Calculus.
1
2
3
…
Go to page
Go
900
Next
1 of 900
Go to page
Go
Next
Last
Filters
Show only:
Loading…
T
Locked
Sticky
Read Before Posting!!
Ted
Feb 20, 2006
Replies
0
Views
39K
Feb 20, 2006
Ted
T
C
How many of the mixed sweets do you get for 10N?
chijioke
Apr 12, 2024
Replies
13
Views
311
Tuesday at 10:54 PM
Dr.Peterson
C
Calculate the average speed
chijioke
Apr 7, 2024
Replies
7
Views
265
Apr 11, 2024
Dr.Peterson
K
Help with business problem
Kessdog11
Apr 7, 2024
Replies
2
Views
502
Apr 9, 2024
Dr.Peterson
G
Finding an equilateral triangle inscribed inside a square of side 4
gamaz321
Apr 6, 2024
Replies
11
Views
228
Apr 7, 2024
Dr.Peterson
G
Solvable Algebra equation?
Gamer30
Apr 6, 2024
Replies
8
Views
196
Apr 7, 2024
blamocur
G
How to find the minimum value of a tricky function
gamaz321
Apr 5, 2024
Replies
14
Views
283
Apr 6, 2024
Steven G
G
How to solve the equation x^-1.5=1
gegogabanana
Mar 29, 2024
Replies
9
Views
291
Apr 1, 2024
khansaheb
K
R
How do I find the nth term of this sequence?
Raanikeri
Mar 27, 2024
Replies
4
Views
252
Mar 28, 2024
Harry_the_cat
S
3 Agent Decision Making Game - Game Theory
sharkywrecks
Mar 28, 2024
Replies
0
Views
31
Mar 28, 2024
sharkywrecks
S
E
Modular arithmetic: i wanted to ask whether the interpreation of X = 361 + 1(mod461 +1) the same as X=362(mod462).
elioruzan
Mar 24, 2024
Replies
5
Views
223
Mar 24, 2024
Dr.Peterson
A
The derivation of Cardanos formulas
Aion
Mar 20, 2024
Replies
2
Views
281
Mar 21, 2024
Aion
A
J
Need Help with Question 14 a, b, c: A grade 9 class earns a profit of 53 cents for each program they sell for the school play....
jhengalala
Mar 20, 2024
Replies
2
Views
147
Mar 20, 2024
Steven G
A
Vectors in equilibrium: A body is acted on by 3 forces in the (x,y)-plane. T_3 = 30.0j N, angle is 20.0 degrees, body is at equilibrium
annaanna
Mar 18, 2024
Replies
7
Views
305
Mar 19, 2024
annaanna
A
K
How to solve this? The first three terms of a different geometric progression are (4/3)cos^2(3theta), (16/9)cos^4(3theta), and (64/27)cos^6(3theta)
Kulla_9289
Mar 16, 2024
2
Replies
27
Views
680
Mar 17, 2024
blamocur
R
Complex Numbers: Find the modulus of (1 + i sqrt{3}). Hence evaluate (1 + i sqrt{3})^3. Give your answer in x + iy form.
reggiwilliams
Mar 16, 2024
Replies
12
Views
288
Mar 17, 2024
reggiwilliams
R
M
Linear Algebra Vectors (Find point P in R3 such that A,B,C and P form a rhombus)
mmedy2311
Mar 15, 2024
Replies
2
Views
216
Mar 16, 2024
Steven G
R
Indices: Two variables x & y satisfy the equation y = 3*4^x. Find 'a' if (a,6) lies on graph. Find 'b' if (-1/2,b) also lies on the graph.
reggiwilliams
Mar 16, 2024
Replies
2
Views
195
Mar 16, 2024
lookagain
L
B
Help in problem of theory of equations: Let a ≠ 0, b, c be integers and sinx, cosx be the rational roots of the equation ax^2+bx+c=0....
banaj
Mar 7, 2024
Replies
14
Views
404
Mar 16, 2024
blamocur
R
Inverse functions and graphing: Find the inverse function for the function y = x^2 - 4x + 5, and draw its graph
reggiwilliams
Mar 15, 2024
Replies
5
Views
160
Mar 15, 2024
Dr.Peterson
A
Complex roots: Given that z = -3/2 + i*sqrt{11}/2 is a root of z^4 - 3z^3 - z^2 + kz + 40 = 0, find...
annaanna
Mar 15, 2024
Replies
10
Views
202
Mar 15, 2024
blamocur
1
2
3
…
Go to page
Go
900
Next
1 of 900
Go to page
Go
Next
Last
You must log in or register to post here.
Forums
Free Math Help
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.
Accept
Learn more…
Top