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lookagain
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lookagain
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08-22-2010
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12-09-2018,
12:52 PM
lookagain
replied to a thread
Solving this quadratic equation on coordinate plane
in
Intermediate/Advanced Algebra
Then stating this is not part of a valid argument. If anything, I would not trust their points of view as much, because they would tend to be more...
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25 replies | 732 view(s)
12-08-2018,
01:55 PM
lookagain
replied to a thread
Richard Feynman's Integral Trick
in
Calculus
You may use integration by parts if you like : \displaystyle\lim_{N \to \infty}\int_0^Nze^{-z}dz After you do the work (and show the work)...
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6 replies | 280 view(s)
12-04-2018,
05:53 PM
lookagain
replied to a thread
Make X the subject of 4logSqt(x) - log3x = logx^-2
in
Intermediate/Advanced Algebra
Yes, also, you must put more complicated exponents and logarithm arguments inside grouping symbols to be correct: New steps ------------- ...
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7 replies | 468 view(s)
12-03-2018,
12:05 AM
lookagain
replied to a thread
Use exactly four 4's to form every integer from 0 to 50
in
Math Odds & Ends
Just as there are primitive (or reduced) Pythagorean triples for right triangles, there are primitive solutions for these "use numbers/digits and...
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40 replies | 1023 view(s)
12-02-2018,
11:39 PM
lookagain
replied to a thread
Use exactly four 4's to form every integer from 0 to 50
in
Math Odds & Ends
Seriously speaking, the Fibonacci function would not be used. Also, Jomo, your example of 4/4! - 4/4! would not be used as a solution, because it...
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40 replies | 1023 view(s)
12-02-2018,
10:55 PM
lookagain
replied to a thread
Use exactly four 4's to form every integer from 0 to 50
in
Math Odds & Ends
In your thread post, you needed to spell out what "usual operators" means. As far as I know they would be: Addition Subtraction & the negation...
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40 replies | 1023 view(s)
11-19-2018,
12:24 PM
lookagain
replied to a thread
President Potty-Mouth
in
Math Odds & Ends
@ mmm4444bot @ Otis @ whatever other usernames you're using I never looked at comments to me past that in that thread. I can see from this post...
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2 replies | 264 view(s)
11-19-2018,
11:17 AM
lookagain
replied to a thread
Solving limit in many ways: lim[x->pi/6] [ (2cos(x) - sqrt{3}) / (6x - pi) ]
in
Calculus
Yes. I worked this out. You might approach it with the following method. Hints: Rewrite it as: \displaystyle\lim_{x \to...
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4 replies | 392 view(s)
11-18-2018,
11:34 PM
lookagain
replied to a thread
Perpendicular line: line through (4, 6) perpendicular to y = -3x + 3
in
Beginning Algebra
It actually rounds to 4.67, but don't use the decimal approximation version. Use the exact value of 14/3. y = (1/3)x + 14/3 From this you see...
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12 replies | 715 view(s)
11-14-2018,
01:00 PM
lookagain
replied to a thread
Another Way
in
Math Odds & Ends
No, you 1) should be able to show independently how you transform the original expression to the final expression, and 2) show detailed steps to...
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2 replies | 306 view(s)
11-14-2018,
12:32 PM
lookagain
replied to a thread
Finding the domain of y = sqrt(3x + 2)
in
Intermediate/Advanced Algebra
Did you intend f(x) = \sqrt{x - 4 \ } \ instead? x - 4 \ \ge \ 0 x \ \ge \ 4
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17 replies | 810 view(s)
11-12-2018,
01:54 PM
lookagain
replied to a thread
Series Question: Divergence or Converence of sum[n=1,infty][(-1)^{n+1} (n^2/(n^3+1))]
in
Calculus
Make sure you use grouping symbols as mentioned above. ____________________________________________________________ Instead of the derivative...
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6 replies | 413 view(s)
11-12-2018,
12:59 PM
lookagain
replied to a thread
Find a,b so (x-5) and (x+3) are factors of x^4+ax^3-34x^2-76x+b
in
Intermediate/Advanced Algebra
(x - 5) is a factor of the polynomial, so the corresponding root is 5. (x + 3) is a factor of the polynomial, so the corresponding root is -3. ...
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2 replies | 281 view(s)
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