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• 05-22-2018, 01:40 PM
As others referred to, for this to make sense/work out, it must be written out equivalent to: y = (6-2x)^(1/2) The grouping symbols around...
5 replies | 129 view(s)
• 05-20-2018, 06:15 PM
Your solutions to the equation of your example don't match it. Maybe you intended the equation \ \ x^2 - 2 = 0.
7 replies | 205 view(s)
• 05-19-2018, 01:15 PM
\dfrac{log(31.25)}{log(2.5)} \ = \ 3.756... It approximately equals 3.76.
11 replies | 315 view(s)
• 05-16-2018, 10:52 AM
You need grouping symbols: (x^k - y^k)/(x - y) = x^(k - 1) + yx^(k - 2) + ... + y^(k - 2)x + y^(k - 1) Or, add one pair of brackets to made...
22 replies | 789 view(s)
• 05-13-2018, 09:46 AM
That downward arrow must mean "approaching from the right." And the upward arrow must mean "approaching from the left."
3 replies | 173 view(s)
• 05-05-2018, 12:06 AM
Incorrect. Every real number can be multiplied by itself, including zero. 0*0 \ = \ 0 I don't know what you were getting at.
7 replies | 454 view(s)
• 05-04-2018, 11:48 PM
This site does not use , for Latex. Here is what you intended: If j here is the "imaginary unit" then multiply both numerator and denominator...
3 replies | 173 view(s)
• 05-04-2018, 11:40 PM
You are incorrect. Follow Subhotosh Khan's hint. That will factor as the product of two trinomials, each having integer coefficients.
3 replies | 156 view(s)
• 04-30-2018, 08:02 PM
n = 100/(2.34%)
6 replies | 274 view(s)
• 04-30-2018, 06:27 PM
You need 2.34% of something . If 2.34% of the total number of people = 100 people, how many people would 100% of the total number of people be? ...
6 replies | 274 view(s)
• 04-30-2018, 06:03 PM
\Gamma{(n)} \ = \ (n - 1)! \ \ \ \ \ \ \ Each \ \ n \ \ is \ \ a \ \ positive \ \ integer. \ \ - - - - - - - - - - - - - - - - - - - - - - - -...
11 replies | 658 view(s)
• 04-30-2018, 11:36 AM
log(1 + 9) + 92 = 93
11 replies | 658 view(s)
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