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lookagain
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lookagain
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08-22-2010
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10-08-2017,
03:30 PM
lookagain
replied to a thread
Function f such that f (x) = ln (5×-10), for x >2; find range of function & inverse
in
Intermediate/Advanced Algebra
You must have meant when x = 2.001, because ln(5*2.001 - 10) < 0. cired2002, the numerical values for the domain of the original function are...
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2 replies | 285 view(s)
10-01-2017,
02:58 PM
lookagain
replied to a thread
I think I found the highest known prime number.
in
Advanced Math
No, the proof does not conclude that. The proof concludes that either u is prime, or u has prime factors larger than the supposed largest prime in...
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7 replies | 577 view(s)
09-27-2017,
11:57 AM
lookagain
replied to a thread
Stuck on how to do: given f(x)= 2x^2-5x+1 simplify f(x+5)-f(x)/5
in
Intermediate/Advanced Algebra
5x^(-3/6) + x^(-11/6) 5x^(-1/2) + x^(-11/6) . . . . I recommend you leaving it in this form. However, check with the instructions/instructor...
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7 replies | 430 view(s)
09-25-2017,
10:44 AM
lookagain
replied to a thread
Stuck on how to do: given f(x)= 2x^2-5x+1 simplify f(x+5)-f(x)/5
in
Intermediate/Advanced Algebra
Type grouping symbols around your fractional exponents. Use other grouping symbols for clarity is a recommendation. Space out your characters for...
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7 replies | 430 view(s)
09-23-2017,
12:48 PM
lookagain
replied to a thread
Integration problem: area enclosed by y=x3-3x2+3x and y=13x
in
Calculus
No, show it as the following for your instructor/course work and work it through. You should show your work here if you get stuck. The area...
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9 replies | 491 view(s)
09-23-2017,
10:45 AM
lookagain
replied to a thread
Right triangle in a circle
in
Geometry and Trig
Not necessarlly. What the OP gave to you is flawed. A right triangle is inscribed in a circle. The problem needs that. It's...
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7 replies | 352 view(s)
09-21-2017,
05:10 PM
lookagain
replied to a thread
Induction Proof
in
Intermediate/Advanced Algebra
Here, the domain of n is necessarily being taken as that of the integers, because the context is mathematical induction.
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3 replies | 262 view(s)
09-21-2017,
04:45 PM
lookagain
replied to a thread
Inverse Functions
in
Intermediate/Advanced Algebra
f(x) = -10x2+1 has no inverse function, because it is not a one-to-one function. f(x) = -10x2+1, \ x \ge 0 is a one-to-one function, and it has...
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2 replies | 204 view(s)
09-18-2017,
01:49 PM
lookagain
replied to a thread
Limit Question- lim[x->2] (sqrt(6-x)-2)/(sqrt(3-x)-1)
in
Calculus
If you wanted to use conjugates of the numerator and the denominator, you could begin with these steps: \displaystyle\lim_{x\to \ 2} \...
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2 replies | 231 view(s)
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