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• Today, 02:37 PM
What in the world are you studying? It appears that you need a personal tutor for basic arithmetic. Or you are a troll.
7 replies | 63 view(s)
• Today, 12:37 PM
OK, your first idea was absolutely on target: solve for a and then substitute the value or values found into the second expression. Perfect. There...
3 replies | 39 view(s)
• Today, 11:28 AM
No, I think it is far more fundamental than that. He has no clue about any type of number other than non-negative integers. He may also not know what...
7 replies | 63 view(s)
• Yesterday, 10:22 PM
Actually tk the original statement does not say what I said. I just tried to reverse engineer the thing to see how I could get fixed payments...
25 replies | 466 view(s)
• Yesterday, 08:14 PM
I suspect there is a mistake in the statement of the problem. Notice that it would take infinite time to distribute 1 percent of the phone books, a...
8 replies | 64 view(s)
• Yesterday, 06:23 PM
I have only loosely followed this. It looks like some sort of hocus pocus. I can make sense of this as a loan with an annual rate of 7.9%...
25 replies | 466 view(s)
• Yesterday, 02:23 PM
Induction (a - b)^1 = a - b = a + (-\ b) = \{a + (-\ b)\}^1. \therefore \exists \text { non-empty set } \mathbb K \text { such that } x \in...
2 replies | 47 view(s)
• Yesterday, 08:11 AM
It is courteous to do so but not necessary. What is objected to is bumping to the top to try to get a quicker answer.
7 replies | 139 view(s)
• 09-23-2018, 11:27 PM
I cannot remember the formula, and it is a tricky counting problem. How many ways can you get all four correct. Obviously, just 1. How many...
9 replies | 115 view(s)
• 09-23-2018, 08:29 PM
First, I want to thank you for appearing to have read "read before posting." What is edx? It appears that some information is missing. 0.108...
3 replies | 67 view(s)
• 09-23-2018, 12:49 PM
I am truly not sure what you are even trying to do. But the unit digit of the square of one of the decimal digits is in the set {0, 1, 4, 5, 6,...
16 replies | 359 view(s)
• 09-23-2018, 11:07 AM
8 replies | 182 view(s)
• 09-21-2018, 08:19 PM
With a certain level of skill, one can present almost any analysis in a plausible but misleading manner. It is the stock in trade of politicians,...
9 replies | 229 view(s)
• 09-21-2018, 10:40 AM
I must admit to finding the question obscurely phrased. As I read the instruction, you are NOT to give an answer in summation notation, but rather to...
7 replies | 254 view(s)
• 09-20-2018, 05:00 PM
To build a bit on Dr. Peterson's post: P(A) \ge 0 \text { and } P(B) = 0 \implies P(A \text { and } B) = 0 \implies P(A \text { and } B) = P(A) *...
9 replies | 248 view(s)
• 09-20-2018, 07:30 AM
JeffM replied to a thread Wall of Shame in News
That didnt take long. :D
18 replies | 647 view(s)
• 09-19-2018, 08:54 PM
JeffM replied to a thread Wall of Shame in News
I'd offer to help with this public service, but I fear my responses would not be appropriate for a site that is open to children.
18 replies | 647 view(s)
• 09-19-2018, 10:01 AM
Here is a completely different way to attack the problem. It is given that n is a positive integer. Therefore n is either even or odd. If n is...
7 replies | 392 view(s)
• 09-18-2018, 03:29 PM
This is a duplicate of a thread at MMF.
5 replies | 159 view(s)
• 09-18-2018, 01:23 PM
Do you see that when you multiply by (1/23) and divide by (1/23), you are accomplishing nothing. I am going to use D_i to mean that customer goes...
9 replies | 245 view(s)
• 09-17-2018, 10:16 AM
And meanwhile no one has given the algebraic proof I could not find, nor shown that such a proof is impossible. You guys are too busy with gluttony...
10 replies | 427 view(s)
• 09-16-2018, 04:34 PM
What reason did the teacher give for why your answer was wrong? What was the exact wording of the problem? I do not love your answer because it...
6 replies | 179 view(s)
• 09-16-2018, 04:20 PM
I am not going to talk about mistakes II, IV, and V because you were already on the wrong path, but you should try to find them on your own. Your...
5 replies | 155 view(s)
• 09-16-2018, 02:01 PM
Well, despite considerable effort, I have not found an algebraic proof. I do not assert that an algebraic proof is impossible; indeed I am relatively...
4 replies | 280 view(s)
• 09-15-2018, 09:17 PM
Finding a finite number of values that satisfy relationships among n unknowns generally requires specification of at least n relationships among...
5 replies | 191 view(s)
• 09-14-2018, 09:35 PM
I doubt the original poster is going to answer because this post was made 19 months ago. Let's try this. What is the relevant payment? What is the...
5 replies | 1038 view(s)
• 09-14-2018, 06:35 PM
No, the camel drover buys artichokes. 100 bananas will buy 800 artichokes at the destination, and the camel only eats 1 artichoke every 2 days. And...
8 replies | 271 view(s)
• 09-14-2018, 01:27 PM
0.47 = \dfrac{4}{10} + \dfrac{7}{100} > \dfrac{4}{10} \ \because \ \dfrac{7}{100} > 0. 0.0470 = \dfrac{4}{10} + \dfrac{7}{100} + \dfrac{0}{1000} =...
21 replies | 607 view(s)
• 09-13-2018, 02:46 PM
It is not the clearest sentence possible although it is clear in context. What is meant is: "Of all possible numbers expressed with two decimal...
29 replies | 1036 view(s)
• 09-13-2018, 02:19 PM
OK. The mechanics are simple. We want to calculate c = b - a, where a, b, or both have one or more digits to the right of the decimal point. ...
21 replies | 607 view(s)
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