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• Yesterday, 03:35 PM
If he is, I am not moving downstream.
6 replies | 66 view(s)
• Yesterday, 03:29 PM
This is a duplicate of a thread at MMF.
2 replies | 45 view(s)
• Yesterday, 01:23 PM
Do you see that when you multiply by (1/23) and divide by (1/23), you are accomplishing nothing. I am going to use D_i to mean that customer goes...
9 replies | 176 view(s)
• 09-17-2018, 10:16 AM
And meanwhile no one has given the algebraic proof I could not find, nor shown that such a proof is impossible. You guys are too busy with gluttony...
10 replies | 369 view(s)
• 09-16-2018, 04:34 PM
What reason did the teacher give for why your answer was wrong? What was the exact wording of the problem? I do not love your answer because it...
6 replies | 119 view(s)
• 09-16-2018, 04:20 PM
I am not going to talk about mistakes II, IV, and V because you were already on the wrong path, but you should try to find them on your own. Your...
5 replies | 92 view(s)
• 09-16-2018, 02:01 PM
Well, despite considerable effort, I have not found an algebraic proof. I do not assert that an algebraic proof is impossible; indeed I am relatively...
4 replies | 245 view(s)
• 09-15-2018, 09:17 PM
Finding a finite number of values that satisfy relationships among n unknowns generally requires specification of at least n relationships among...
5 replies | 137 view(s)
• 09-14-2018, 09:35 PM
I doubt the original poster is going to answer because this post was made 19 months ago. Let's try this. What is the relevant payment? What is the...
5 replies | 993 view(s)
• 09-14-2018, 06:35 PM
No, the camel drover buys artichokes. 100 bananas will buy 800 artichokes at the destination, and the camel only eats 1 artichoke every 2 days. And...
8 replies | 229 view(s)
• 09-14-2018, 01:27 PM
0.47 = \dfrac{4}{10} + \dfrac{7}{100} > \dfrac{4}{10} \ \because \ \dfrac{7}{100} > 0. 0.0470 = \dfrac{4}{10} + \dfrac{7}{100} + \dfrac{0}{1000} =...
21 replies | 440 view(s)
• 09-13-2018, 02:46 PM
It is not the clearest sentence possible although it is clear in context. What is meant is: "Of all possible numbers expressed with two decimal...
29 replies | 727 view(s)
• 09-13-2018, 02:19 PM
OK. The mechanics are simple. We want to calculate c = b - a, where a, b, or both have one or more digits to the right of the decimal point. ...
21 replies | 440 view(s)
• 09-13-2018, 09:23 AM
You should be banned. You have asked questions about calculus, but now emphatically deny that you can subtract decimal numbers.
21 replies | 440 view(s)
• 09-12-2018, 10:26 AM
It should be intuitively obvious that, if y is greater than 1, y is positive and so therefore must x be. Moreover, it should be equally obvious that,...
3 replies | 102 view(s)
• 09-09-2018, 11:36 AM
I do not know whether the OP stll has any interest in this thread. I have been traveling and have not had time to look for a proof. I suspect the OP...
4 replies | 245 view(s)
• 09-07-2018, 11:54 AM
If a problem has a solution in the real numbers, it also has a solution in the complex numbers. If a problem has a solution in the complex...
7 replies | 194 view(s)
• 09-06-2018, 02:26 PM
JeffM replied to a thread Zero Discussion in Math Odds & Ends
I think you misread me. Under my preferred definitions, zero is even. But I gave commonly accepted definitions under which zero is not included...
24 replies | 667 view(s)
• 09-06-2018, 10:56 AM
JeffM replied to a thread Zero Discussion in Math Odds & Ends
Arguments about definitions are neverending. A common definition of a natural number is the set {1, 2, 3, 4, ... }. And a common definition of an...
24 replies | 667 view(s)
• 09-06-2018, 08:21 AM
I have no idea how or why money decays, but that sort of question is not one that relates to mathematics at all. As a matter solely of descriptive...
5 replies | 198 view(s)
• 09-05-2018, 09:43 PM
Let's deal first with the low hanging fruit. 2 - 3 + 3 - 2 = 2 - 2 + 3 - 3 = 0 + 0 = 0. Any questions about that one? (7 - 9)(+\ 4) =...
7 replies | 230 view(s)
• 09-05-2018, 11:08 AM
The discriminant plus factoring makes for a very simple solution given the knowledge that we want only integer answers. 4k^2 - 3 = n^2 \implies...
7 replies | 219 view(s)
• 09-04-2018, 09:49 AM
This is likely to be a very unsatisfactory answer. As I understand it, you have two variables for which you have data points. You want to find...
5 replies | 198 view(s)
• 09-04-2018, 09:12 AM
Glad to have helped. As you will see by rereading my first post, I gave you an example with four independent variables in the model, but only two in...
9 replies | 198 view(s)
• 09-04-2018, 07:26 AM
To supplement my previous answer, if n independent variables are involved in the model and only k < n of those variables determine the objective...
9 replies | 198 view(s)
• 09-03-2018, 10:13 PM
Well there is nothing wrong with your set of assumptions in terms of theoretical economics. Theoretical economics permits you to make any assumptions...
9 replies | 198 view(s)
• 09-03-2018, 01:26 PM
You must define relationships among all the variables. Your notation is a bit clumsy, and I suspect that the problem is not set up correctly. As...
9 replies | 198 view(s)
• 09-03-2018, 10:25 AM
mq = -\ 3nm + 2nq \implies 3nm + mq = 3nm - 3nm + 2nq \implies 3nm + mq = 2nq \implies 3nm + mq - mq = 2nq - mq \implies 3nm = 2nq - mq...
4 replies | 165 view(s)
• 09-02-2018, 08:07 AM
Two points are not orthogonal. A good first step is to determine the function that describes the plane to which w_2 is perpendicular. Can you do...
3 replies | 204 view(s)
• 09-02-2018, 07:51 AM
They are asking you to find the locus of points, each of which has a distance from itself to (0, 4) that is three times the distance from itself to...
6 replies | 290 view(s)
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