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• Today, 02:02 PM
ksdhart2 replied to a thread Pre-Calculus Question in Calculus
Often times with problems like this, the trick is to gather as much information as you can from the problem and then synthesize it into something...
1 replies | 34 view(s)
• 08-20-2017, 01:01 PM
Yes, that's correct, but there's also a sign error. In this problem, it won't manifest itself, but in the future it could mess you up big time. The...
2 replies | 101 view(s)
• 08-19-2017, 10:37 PM
No one except the author of the exercise in question can say with any certainty, but my interpretation of that is that if your first throw hits the...
5 replies | 216 view(s)
• 08-18-2017, 04:16 PM
What are your thoughts? What have you tried? For instance, you first calculated the indefinite integral \displaystyle \int \: \frac{1}{1+ln(t)} and...
2 replies | 166 view(s)
• 08-18-2017, 01:10 AM
This is a wonderful exercise to help you practice your problem solving and pattern recognition skills. These skills will prove immensely helpful in...
3 replies | 210 view(s)
• 08-18-2017, 12:56 AM
ksdhart2 replied to a thread [x] in Arithmetic
It can mean that, but it doesn't always. Most often, I see the square brackets simply used for nested grouping symbols. For instance, rather than 1 /...
3 replies | 262 view(s)
• 08-18-2017, 12:47 AM
No. In this case, e is the mathematical constant such that e^{ln(x)} = x. Another way of defining it is \displaystyle e = \sum^{\infty}_{n=0} \:...
4 replies | 171 view(s)
• 08-17-2017, 07:31 PM
I'll assume that by Acos(x - B), you mean A * cos(x - B) and not the common notation for arccosine (aka inverse cosine). If that's the case, then my...
4 replies | 171 view(s)
• 08-16-2017, 03:44 PM
7 replies | 255 view(s)
• 08-16-2017, 01:40 AM
Most of your work is good, except for a few things. One, the Pythagorean Theorem a2 + b2 = c2 is about the sides of a triangle, not the angles. Two,...
7 replies | 255 view(s)
• 08-15-2017, 01:30 AM
It seems to me that the bulk of your confusion over "is it 32.5 or 1.57" is due to neglect of units. The student rides at 20 km/h, that is 20...
3 replies | 360 view(s)
• 08-15-2017, 01:00 AM
First off, I'll guess that these are typos and are meant to read 'y'. That aside, your method is a bit flawed because it only works for polynomials...
4 replies | 239 view(s)
• 08-15-2017, 12:36 AM
Well, it's impossible for us to discern much of anything without seeing the actual problem text and/or your workings on it... but my best guess is...
3 replies | 163 view(s)
• 08-14-2017, 09:11 PM
4 replies | 305 view(s)
• 08-13-2017, 03:33 PM
Okay, so I'll begin by copying the text from the image for those who might not be so inclined to visit an outside link: Your working was to...
4 replies | 305 view(s)
• 08-13-2017, 01:10 PM
I can't say as though I've seen the term "independent" used in this context before, but my best guess is that you're correct. If an expression can be...
7 replies | 260 view(s)
• 08-13-2017, 11:49 AM
What are your thoughts? What have you tried? For instance, your title says "Integration by Substitution." Which expression in x did you pick for your...
2 replies | 246 view(s)
• 08-13-2017, 12:42 AM
Well, as you read in the Read Before Posting thread, providing answers isn't what we do here. Being that you've shown no work of your own on these...
2 replies | 174 view(s)
• 08-12-2017, 01:45 PM
Well, it's true that equivalent sets have will always have the same cardinality, but that's not why they're equivalent. It's sort of like how planes...
2 replies | 203 view(s)
• 08-11-2017, 03:58 PM
I see you've found the answer you were after, and that's great. :) But for the benefit of any future students who might stumble upon this thread,...
4 replies | 261 view(s)
• 08-11-2017, 02:40 PM
Just adding this to the public record. This exact problem was also asked on AskMath over at Reddit (possibly by the OP? possibly by a classmate? The...
3 replies | 317 view(s)
• 08-09-2017, 09:42 PM
Having used that exact calculator, I can attest to the fact that the more complicated functions are often a pain in the butt to find and use. My...
1 replies | 193 view(s)
• 08-09-2017, 09:28 PM
Ah, okay. Armed with this correction, your derivative is absolutely correct. What did you get for the next step, when you plug in t = 15?
5 replies | 383 view(s)
• 08-09-2017, 04:36 PM
Well, I'm assuming the superscript exponents didn't carry over from when you copied-and-pasted, and you actually meant: \epsilon = 4 \cdot 10 -...
5 replies | 383 view(s)
• 08-07-2017, 11:05 AM
I think I understand what you're getting at, and it was something that frustrated me for a very long time. For one thing, my recollection is that...
20 replies | 1149 view(s)
• 08-07-2017, 10:44 AM
Oof! Can't believe I didn't notice this myself. I didn't real carefully enough I suppose. I had thought they were asking for a solution of the form y...
14 replies | 818 view(s)
• 08-06-2017, 07:19 PM
Erm, sorry, but I hope you'll bear with me, as I'm really having trouble deciphering what it is you're asking. I think you're asking about something...
4 replies | 403 view(s)
• 08-05-2017, 12:13 PM
Certainly. Powers involving e can often seem mystical and magical, but they're really not. They just involve using the properties of exponents and...
14 replies | 818 view(s)
• 08-04-2017, 10:28 PM
First off, a big thank you for showing us your efforts! Lately it seems like we've been inundated with people who either didn't read the rules at...
14 replies | 818 view(s)
• 08-03-2017, 08:23 PM
The basic shape of the graph will stay the same, being that of 1/x, but the specific values for any given x will change according to the constant. It...
7 replies | 471 view(s)
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